Answer:
The mass of the receiver is 85 kg.
Explanation:
Given:
Mass of the tackler (M) = 130 kg
Mass of the receiver = 'm' (Assume)
Initial velocity of the receiver (u) = 0 m/s
Initial velocity of the tackler (U) = 3.8 m/s
Final combined velocity (v) = 2.3 m/s
So, as per question, the momentum is conserved. Therefore, the total initial momentum is equal to the total final momentum.
Total initial momentum is given as:
[tex]P_i=mu+MU\\\\P_i=0+130\times 3.8\\\\P_i=494\ kg\cdot m/s[/tex]
Total final momentum is given as:
[tex]P_f=(m+M)v\\\\P_f=(m+130)2.3[/tex]
Now, as per momentum conservation:
[tex]P_f=P_i\\\\(m+130)2.3=494\\\\m+130=\frac{494}{2.3}\\\\m=214.78-130\\\\m=84.78\ kg\approx85\ kg[/tex]
Therefore, the mass of the receiver is 85 kg.