Answer:
The 98% confidence interval for the mean amount of money spent on lunch per week for all students is between $13.3 and $16.7.
Step-by-step explanation:
A confidence interval has the following format.
[tex]\mu_{x} \pm M[/tex]
In which [tex]\mu_{x}[/tex] is the mean of the sample and M is the margin of error.
In this problem, we have that:
[tex]\mu_{x} = 15, M = 1.7[/tex]
[tex]\mu_{x} - M = 15 - 1.7 = 13.3[/tex]
[tex]\mu_{x} + M = 15 + 1.7 = 16.7[/tex]
The 98% confidence interval for the mean amount of money spent on lunch per week for all students is between $13.3 and $16.7.
