Forty families gathered for a fund-raising event. Suppose the individual contribution for each family is normally distributed with a mean and a standard deviation of $115 and $35, respectively. The organizers would call this event a success if the total contributions exceed $5,000. What is the probability that this fund-raising event is a success?

Respuesta :

Answer:

3.51% probability that this fund-raising event is a success

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the total sum of a sample of size n, we have mean [tex]n*\mu[/tex] and standard deviation [tex]s = \sqrt{n}*\sigma[/tex]

In this problem, we have that:

[tex]n = 40, \mu = 40*115 = 4600, \sigma = 35, s = \sqrt{40}*35 = 221.36[/tex]

The organizers would call this event a success if the total contributions exceed $5,000. What is the probability that this fund-raising event is a success?

This is 1 subtracted by the pvalue of Z when X = 5000. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{5000 - 4600}{221.36}[/tex]

[tex]Z = 1.81[/tex]

[tex]Z = 1.81[/tex] has a pvalue of 0.9649

1 - 0.9649 = 0.0351

3.51% probability that this fund-raising event is a success