Answer:
0.055 mol
Explanation:
There is some info missing. I think this is the original question.
Ammonium perchlorate is a powerful solid rocket fuel, used in the Space Shuttle boosters. It decomposes into nitrogen gas, chlorine gas, oxygen gas and water vapor, releasing a great deal of energy. Calculate the moles of oxygen produced by the reaction of 0.055 mol of ammonium perchlorate. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.
Let's consider the decomposition of ammonium perchlorate.
2 NH₄ClO₄(s) → N₂(g) + Cl₂(g) + 2 O₂(g) + 4 H₂O
The molar ratio of NH₄ClO₄(s) to O₂(g) is 2:2. We can use this relationship to find the moles of O₂(g) produced by the decomposition of 0.055 mol of NH₄ClO₄(s).
0.055 mol NH₄ClO₄ × (2 mol O₂/2 mol NH₄ClO₄) = 0.055 mol O₂
