contestada

A rope connects boat A to boat B. Boat A starts from rest and accelerates to a speed of 9.5 m/s in a time t = 47 s. The mass of boat B is 540 kg. Assuming a constant frictional force of 230 N acts on boat B, what is the magnitude of the tension in the rope that connects the boats during the time that boat A is accelerating?

Respuesta :

aabdulsamir

Answer: 339.148N

Explanation:

Data

Time (t) = 47s

U = 0m/s

V = 9.5m/s

Mass of B = 540kg

Frictional force on B = 230N

Both boats are connected so if A moves, B moves too.

Acceleration of boat A =?

Using equation of motion,

V = u + at

9.5 = 0 + a*47

a = 9.5 / 47

a = 0.2021 m/s²

The force required to accelerate boat B since it's the same force moving both boats =?

F = Mass * acceleration

F = 540 * 0.2021 = 109.14N

A frictional force of 230N exists on boat B

Total force (Tension) = frictional force + normal force = (109.15 + 230)N = 339.148N

pstnonsonjoku

The tension that acts on the rope connecting the two boats is 338 N.

We can see that boat B is being dragged along by boat A. We have to determine the magnitude of acceleration on the boat.

We have to use the formula;

v = u + at

v = 9.5 m/s

u = 0 m/s

a = ?

t = 47 s

a = v - u/t

a = 9.5 - 0/47

a = 0.2 ms-2

The tension force is the net force that moves boat B forward. The frictional force is 230 N.

Hence;

Net force = -Ff + Tension force

Tension force = Net force + Ff

Note Ff = frictional force

Tension force = (540 kg × 0.2 ms-2) + 230 N

Tension force = 338 N

Learn more: https://brainly.com/question/24381583

Otras preguntas