Respuesta :
6sin2(x)+2sin2(2x)=5-----------------------------
3(1−cos(2x))+(1−cos(4x))=53cos(2x)+cos(4x)+1=03cos(2x)+(2cos2(2x)−1)+1=02cos2(2x)+3cos(2x)=0cos(2x)(cos(2x)+32)=0
3(1−cos(2x))+(1−cos(4x))=53cos(2x)+cos(4x)+1=03cos(2x)+(2cos2(2x)−1)+1=02cos2(2x)+3cos(2x)=0cos(2x)(cos(2x)+32)=0
After solving the given equation, I’ve come up with the answer cos(2x) (cos(2x) + [tex] \frac{3}{2} [/tex]) = 0
I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.