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A peregrine falcon dives at a pigeon. The falcon starts downward from rest with free-fall acceleration. If the pigeon is 56.0 m below the initial position of the falcon, how long does the falcon take to reach the pigeon? Assume that the pigeon remains at rest.


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Respuesta :

 

The solution would be like this for this specific problem:

 

v = ? 
u = 0.0 m/s 
a = 9.8 m/s^2 
s = 56.1 m 

v^2 = (0.0 m/s)^2 + [2 * (9.8 m/s^2) * (56 m) ] 
v^2 = 2 * (9.8 m/s^2) * (56 m) 
v^2 = 1,097.6 m^2/s^2 
v = SQRT {1,097.6 m^2/s^2 } 

v = 33.1 m/s

v = u + at 

(v - u) / a = t 

[ (33.1 m/s) - (0.0 m/s) ] / (9.8 m/s^2) = 3.38 seconds

If the pigeon is 56.0 m below the initial position of the falcon, it will take 3.38 seconds for the falcon to reach the pigeon. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

mnhlabatsi7

Answer:

3.4 s

Explanation

The first step is to write down everything we have then we can decide on the equation of linear motion to use

initial velocity = 0 m/s

acceleration = g = 9.81 m/s²

time (t)= ? that is what the question is asking.

So our equation of choice must have all these variables

[tex]s = ut + \frac{at^{2} }{2} \\\\56 = (0)(t) + \frac{9.81*t^{2} }{2} \\\\112 = 9.81t^{2} \\\\t = 3.4 s[/tex]