Help please! I'm just uncertain about what d is.

Complete the paragraph proof.

Given: angle 1 and angle 2 are supplementary, and angle 2 and angle 3 are supplementary.

Prove: angle 1 ≅ angle 3

By the definition of supplementary angles, angle 1 + angle 2 = _(a) and angle 2 + angle 3 = (b). Then angle one + angle 2 = angle 2 + angle 3 (c). Subtract angle 2 from each side. You get angle 1 = (d), or angle 1 ≅ __(e).

I think that they are the following.

a is 180 degrees.
b is 180 degrees.
c is 360 degrees.
d ???
e is angle 3

What do you think d is? Do you think I am correct?

By the definition of supplementary angles,
a. angle 1 + angle 2 = 180 degrees
b. and angle 2 + angle 3 = 180 degrees
c. Then angle one + angle 2 = angle 2 + angle 3 = 180 degrees
d. Subtract angle 2 from each side. You get angle 1 = angle 3
e. or angle 1 ≅ angle 3

I hope that the above answer is absolutely clear to you.

Answer Link

calculista calculista · Answer 2 · 2019-01-13T20:52:58+01:00

Answer:

Part a) [tex]180\°[/tex]

Part b) [tex]180\°[/tex]

Part c) [tex]180\°[/tex]

Part d) Angle [tex]3[/tex]

Part e) Angle [tex]3[/tex]

Step-by-step explanation:

we know that

If two angles are supplementary

then

their sum is equal to [tex]180\°[/tex]

In this problem

angle 1 and angle 2 are supplementary, and angle 2 and angle 3 are supplementary

so

[tex]m<1+m<2=180\°[/tex] --------> equation A

[tex]m<2+m<3=180\°[/tex] --------> equation B

equate equation A and equation B

[tex]m<1+m<2=m<2+m<3[/tex]

Subtract [tex]m<2[/tex] both sides

[tex]m<1+m<2-m<2=m<2+m<3-m<2[/tex]

[tex]m<1=m<3[/tex]

therefore

m<1≅m<3