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A 10 kg box, sliding to the right across a rough horizontal floor, accelerates at -2 m/s^2 due to the force of friction. Calculate the coefficient of kinetic friction between the box and the floor and the magnitude of the net force acting on the box.

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meerkat18
According to Newton's second law of motion, Fnet = m x a. From the given above,
                                    Fnet = (10 kg) x (-2 m/s²) = -20 N
The force of friction, Ff, which is a negative force is the product of the normal force and the coefficient of friction,
                                       Ff = 20 N = k x (10 kg x 9.8 m/s²)
The value of k from the equation is 0.204. Thus, the coefficient of friction is equal to 0.204. 

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