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Express the complex number in trigonometric form.

-6i


6(cos 0° + i sin 0°)

6(cos 270° + i sin 270°)

6(cos 180° + i sin 180°)

6(cos 90° + i sin 90°)

Respuesta :

meerkat18
we can answer this problem asking to express the complex number -6i in trigonometric form. first thing to do is to evaluate the given expressions

cos 0 is 1
sin 0 is 0 
sin 180 is 0
cos 180 is -1
cos 270 is 0
sin 270 is -1
sin 90 is 1
cos 90 is 0.
Hence the answer to this problem is B.6(cos 270° + i sin 270°)

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