Respuesta :
[tex](n+1)^2-n^2=35\\
n^2+2n+1-n^2=35\\
2n=34\\
n=17\\
n+1=18[/tex]
17 and 18
17 and 18
the numbers are n and n+1
the difference is 35
(n+1)^2-n^2=35
expand
n^2+2n+1-n^2=35
combine like terms
2n+1=35
minus 1 from oth sides
2n=34
divide by 2
n=17
the other number is 1 more
17 and 18
check
17^2=289
18^2=324
324-289=35
17 and 18
the difference is 35
(n+1)^2-n^2=35
expand
n^2+2n+1-n^2=35
combine like terms
2n+1=35
minus 1 from oth sides
2n=34
divide by 2
n=17
the other number is 1 more
17 and 18
check
17^2=289
18^2=324
324-289=35
17 and 18