1. The molar mass of CuSO4 is 159.61 g/mol. Given that there is only 0.96 g left after dehydration, the number of moles CuSO4.xH2O is,
m = 0.96 g / 159.61 g/mol = 6.014 x 10^-3
Thus,
(6.014 x 10^-3 moles)(156.61 + x(18)) = 1.50
The value of x is 5.15. For whole numbers, x is 5.
2. The number of moles of KAl(SO4) is 0.0116 moles. The molar mass of the given hydrate is 474.388 g/mol. Thus, the initial mass is 0.0116 moles x 474.388 g/mol which is equal to 5.51 g.