ThatCreepyBoy
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PLEASE ANSWER FAST!!!


Rectangle J'K'L'M' shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applied on trapezoid STUV, as shown below:

Rectangle JKLM is drawn on the grid with vertices J at negative 6, 2. K is at negative 3, 2. L is at negative 3, 4. M is at negative 6, 4. Rectangle J prime K prime L prime M prime is drawn with vertices J prime is at 1, 7. K prime is at 4, 7. L prime is at 4, 9. M prime is at 1, 9. Trapezoid STUV is drawn with vertices S is at 3, negative 6. T is at 6, negative 6. U is at 6, negative 3. V is at 2, negative 3.

What will be the location of T' in the image trapezoid S'T'U'V'?
(10, −1)
(10, 1)
(13, 1)
(13, −1)

Respuesta :

antonsandiego
It's hard enough to solve this task because you've not attached any illustrations to that question. But I think you can find help by using special soft to create images of the figures by given coords and find the missing point T'. Anywhay I think the second option is suitable.

The correct answer is:

(13, −1)

Explanation:

The points of the pre-image JKLM are:

J(-6, 2); K(-3, 2); L(-3, 4); M(-6, 4).

The points of the image J'K'L'M' are:

J'(1, 7); K'(4, 7); L'(4, 9); M'(1, 9).

Comparing the x- and y-coordinates of the pre-image and image points, we can see that the x-coordinate is 7 larger each time and the y-coordinate is 5 larger; this means that the translation <7, 5> has been applied.

Applying this same transformation to STUV, we get point T' at

(6+7, -6+5) = (13, -1)

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