Respuesta :

Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?


–5

Answer:

The correct option is 1.

Step-by-step explanation:

The given quadratic equation is

[tex]x^2+bx+5=0[/tex]

A quadratic equation [tex]ax^2+bx+c=0[/tex] have to real solution if the value of discriminant is garter than 0.

[tex]b^2-4ac>0[/tex]

[tex]b^2-4(1)(5)>0[/tex]

[tex]b^2-20>0[/tex]

Add 20 on both the sides.

[tex]b^2>20[/tex]

It is possible if

[tex]b<-\sqrt{20}, b>\sqrt{20}[/tex]

[tex]b<-4.472, b>4.472[/tex]

Since -5<-.4.472, therefore option 1 is correct.