Respuesta :
Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?
–5
–5
Answer:
The correct option is 1.
Step-by-step explanation:
The given quadratic equation is
[tex]x^2+bx+5=0[/tex]
A quadratic equation [tex]ax^2+bx+c=0[/tex] have to real solution if the value of discriminant is garter than 0.
[tex]b^2-4ac>0[/tex]
[tex]b^2-4(1)(5)>0[/tex]
[tex]b^2-20>0[/tex]
Add 20 on both the sides.
[tex]b^2>20[/tex]
It is possible if
[tex]b<-\sqrt{20}, b>\sqrt{20}[/tex]
[tex]b<-4.472, b>4.472[/tex]
Since -5<-.4.472, therefore option 1 is correct.