Answer:
0.09 M/s is the initial rate when concentration of reactant A is 0.900 M.
Explanation:
A → B
1) Initial concentration of A = [A] =0.300 M
Rate constant of the reaction , k = ?
Rate equation for the second order kinetic is given as:
[tex]R=k[A]^2[/tex]
[tex]0.0100M/s=k[0.300 M]^2[/tex]
[tex]k=\frac{0.0100M/s}{[0.300 M]^2}=0.1111 M^{-1} s^{-1}[/tex]
2) Rate of the reaction when initial concentration of A was 0.900M be R'.
[A] = 0.900M
[tex]R'=k[A]^2[/tex]
[tex]R'=0.1111 M^{-1} s^{-1}\times [0.900 M]^2[/tex]
[tex]R'=0.09 M/s[/tex]
