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Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the distance in 4 h. Car A traveled 22 mph faster than Car B. How fast did Car A travel?._____mph

Respuesta :

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We let x the distance traveled by Car A and y the distance traveled by car B. The speed of car A can be represented as x/2.4 and for Car B is y/4. From the statement given, we can write an equation relating the speed of both cars.

x/2.4 = 22 + y/4

Since y = x, then:


x/2.4 = 22 + x/4

Solving for x, we obtain:

x= 132 meters traveled by both cars

Therefore, Car A has a speed of 55 mph.

Answer:

Speed of car A will be = x+22=33+22 =55 mph

Explanation:

We have given time taken by car A = 2.4 hour

And time taken by car B = 4 hour

It is given that car A is traveling 22 mph faster than car B

Let car B is traveling by a speed of x mph

Then speed of car A = x+22

Now it is given that distance traveled by both the car is same

And we know that distance = speed × time

So [tex]2.4(x+22)=4\times x[/tex]

[tex]x=33m/sec[/tex]

So speed of car A = x+22=33+22 =55 mph

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