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Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the distance in 1.5 h. Car B traveled 15 mph faster than Car A. How fast did Car B travel?

Respuesta :

BjornaDanja
l1=l2
t1=2h
t2=1.5 h
v2=v1+15mph=?
v1=?  
2xv1=1.5x(v1+15mph)
2v1=1.5v1+22.5mph
2v1-1.5v1=22.5 mph
0.5v1=22.5mph
v1=45mph
v2=45mph+15mph
v2=60mph
meerkat18
The distance traveled by the car is the product of its speed and time. Let x be the speed of Car A such that Car B travels at x + 15. From the given condition that the distances they have traveled are equal, the equation becomes,
                                    2x = (1.5)(x + 15)
The value of x from the equation is 45. Thus, Car B travels at a speed of 60 kph. 

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