a box contains 6 red and 5 blue marbles. another box contains 5 red and 8 blue marbles. one box is selected at random and from that bag, one marble is drawn. what is the probability that the marble drawn is blue?

Respuesta :

yadvi3
P(blue) = {(1/2) × (5/11)} + {(1/2) × (8/13)} = 5/22 + 4/13 = 153/286

Answer:

The probability is 0.535

Step-by-step explanation:

Given that a box contains 6 red and 5 blue marbles. another box contains 5 red and 8 blue marbles. one box is selected at random and from that bag, one marble is drawn.

we have to find the probability that the marble drawn is blue.

[tex]Probability=\frac{\text{Favourable outcomes}}{\text{Total number of outcomes}}[/tex]

The probability can be find by formula

=P(first box)P(blue marble drawn from box 1)+P(second box)P(blue marble drawn from box 2)

[tex]=\frac{1}{2}\times \frac{5}{11}+\frac{1}{2}\times \frac{8}{13}[/tex]

[tex]\frac{5}{22}+\frac{8}{26}[/tex]

[tex]\frac{153}{286}=0.535[/tex]