Respuesta :
Answer:
4.2 L O₂ is needed to completely react with 2.8 L hydrogen sulfied.
Explanation:
Without pressure and temperature we cannot calculate the this vale
We assume that the reaction take place under standard Temperature and Pressure(STP).
At STP, One mole ([tex]6.023\times 10^{23}[/tex] particles) of any gas occupied volume 22.4 L.
The balanced equation of this reaction is
[tex]2H_2S+3O_2\rightarrow 2SO_2+2H_2O[/tex]
Now we use molar ratio.
[tex]2.8L\ H_2S . \ \frac{1 mol\ H_2S}{22.4L \ H_2S}\ . \ \frac{3 mol\ O_2}{2 mol \ H_2S} \ . \ \frac{22.4L\ O_2}{1 mol\ O_2}[/tex]
=4.2 L O₂
4.2 L O₂ is needed to completely react with 2.8 L hydrogen sulfied.
