Respuesta :
7.5 M is the concentration of 60 ml of H3PO4 if it is neutralized by 225 ml of 2 M Ba(OH)2.
Explanation:
Data given:
volume of phosphoric acid, Vacid =60 ml
volume of barium hydroxide, Vbase = 225 ml
molarity of barium hydroxide, Mbase = 2M
Molarity of phosphoric acid, Macid =?
the formula for titration is used as:
Macid x Vacid = Mbase x Vbase
rearranging the equation to get Macid
Macid = [tex]\frac{Mbase x Vbase}{Vacid}[/tex]
Macid =[tex]\frac{225 X 2}{60}[/tex]
Macid = 7.5 M
the concentration of the phosphoric acid is 7.5 M and the volume is 60 ml. Thus 7.5 M solution of phosphoric acid is used to neutralize the barium hydroxide solution of 2M.
Answer:
= 5 M
Explanation:
2H3PO4 + 3Ba(OH)2 ----> Ba3(PO4)2 + 3H2O
moles Ba(OH)2 = molarity x litres
= 2 M x 0.225 L
= 0.45 mol
3 moles Ba(OH)2 react with 2 moles H2SO4
So moles H2SO4 = 2/3 x moles Ba(OH)2
= 0.3 mol
molarity = moles / litres
= 0.3 mol / 0.06 L
=5M
