12438 grams of sodium are required to completely react with 19.2 L of Cl, gas at STP.
Explanation:
Data given:
mass of sodium required = ?
volume of Chlorine gas = 19.2 L or 19200 grams
Balanced chemical reaction:
2 Na(s) +
[tex]Cl_{2}[/tex](g) ⇒ 2 NaCl(s)
moles of chlorine gas in the reaction is calculated
atomic mass of chlorine gas = 71 grams/litre
number of moles of chlorine gas = [tex]\frac{mass}{atomic mass}[/tex]
number of moles of chlorine gas = [tex]\frac{19200}{71}[/tex]
number of moles = 270.4 moles
from the balanced reaction,
2 moles of Na, and 1 mole of chlorine gas reacts to form 2 moles of NaCl
270.4 moles of chlorine gas is provided so number of moles of Na will be multiplied by 2, using mole ratio
so number of moles of Na = 270.4 x 2
= 540.8 moles
mass of sodium = number of moles x atomic mass
mass of sodium = 540.8 x 23
= 12438 grams
