The ball will come to ground after 6 seconds.
We have a function of time given by -
f(x) = [tex]-16t^{2} +96t[/tex]
that gives the height of the ball in feet at ' t ' second.
We have to find out after how much time the ball will hit the ground.
In the question given to us above, the type of motion discussed is called ?
The type of motion discussed in the above question is a two - dimensional projectile motion.
We have - h(t) = f(x) = [tex]-16t^{2} +96t[/tex]
Now, in order to find out the time at which the ball will hit the ground again, we will equate h(t) = f(x) = 0
[tex]-16t^{2} +96t=0\\-16t(t - 6)=0\\-16t =0\;\;\;\;\;\;t -6 = 0[/tex]
Now, time can never be 0.
Hence -
t - 6 = 0
t = 6 seconds.
Hence, the ball will come to ground after 6 seconds.
To solve more questions on projectile motion, visit the link below -
https://brainly.com/question/12496840
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