Answer:
In that day 1300 children and 700 adults were admitted.
Step-by-step explanation:
Since the people who enter the park are either adults or children, the sum of these two types of people must be equal to the total amount that entered the park. So we have:
children + adults = 2000
The total amount collected must be the sum of the people that entered the park multiplied by the ticket fee for each type. We have:
1.5*children + 4*adults = 4750
We now have two equations and two variables so we can solve the system.
children + adults = 2000 equation 1
1.5*children + 4*adults = 4750 equation 2
We can multiply the equation 1 by -1.5 and sum it with the equation 2 to solve for adults, we have:
-1.5*children - 1.5*adults = -3500
1.5*children + 4*adults = 4750
2.5*adults = 1750
adults = 1750/2.5 = 700
To solve for children we apply the found value for adults on the equation 1.
children + 700 = 2000
children = 2000 - 700 = 1300
In that day 1300 children and 700 adults were admitted.
Answer:
700 adults and 1300 children
Step-by-step explanation:
Let 'C' represent number of children
'A' represent number of adults
->If 2,000 people entered the park, the equation will be
C+A=2000
C=2000-A ->eq(1)
->$1.50 for children and $4.00 for adults.
$1.50C+$4.00A=$4,750
Substituting for C from above.
$1.50(2000-A)+$4.00A= $4,750
$3000-$1.50A+$4.00A=$4,750
$2.50A = $4,750 - $3000
$2.50A=$1750
A= 700
and for children:
eq(1)=>
C=2000-700
C= 1300
Thus, 700 adults and 1300 children were admitted.
