To solve the problem it is necessary to apply Ohm's law. From this it is established that the voltage is the equivalent to the product between the current and the resistance, therefore we have to,
[tex]V = IR[/tex]
Here,
V = Voltage
I = Current
R = Resistance
Rearranging to find the resistance,
[tex]R = \frac{V}{ I}[/tex]
Replacing,
[tex]R = \frac{100V}{20A}[/tex]
[tex]R = 5\Omega[/tex]
Therefore the resistance should be [tex]5\Omega[/tex]
The resistance should be [tex]\bold { 5\Omega}[/tex] in order to limit the emf to 100 V.
Ohm's law:
It states that the voltage is the equival to the product of the current and the resistance.
[tex]\bold{V =I\times R}[/tex]
Where,
V = Voltage = 100 Volts
I = Current = 20 Ampere
R = Resistance
Put the values and solve it for R
[tex]\bold {R =\dfrac{100}{20}}\\\\\bold {R = 5\Omega}[/tex]
Therefore, the resistance should be [tex]\bold { 5\Omega}[/tex] in order to limit the emf to 100 V.
To know more about Ohm's law
https://brainly.com/question/12865879
