Answer:
Total acceleration will be [tex]160.20rad/sec^2[/tex]
Explanation:
We have given radius of the circle r = 0.685 m
Angular acceleration [tex]\alpha =63.8rad/sec^2[/tex]
Angular speed [tex]\omega =15rad/sec[/tex]
Centripetal acceleration will be
[tex]a_c=\omega ^2r=15^2\times 0.685=154.125rad/sec^2[/tex]
Tangential acceleration will be
[tex]a_t=r\alpha =0.685\times 63.8=43.7rad/sec^2[/tex]
(a) Total acceleration will be equal to
[tex]a=\sqrt{a_t^2+a_c^2}[/tex]
[tex]a=\sqrt{43.7^2+154.125^2}=160.20rad/sec^2[/tex]
So total acceleration will be [tex]160.20rad/sec^2[/tex]
