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Two blocks of masses 6 kg and 10 kg are placed on a horizontal, frictionless surface. A light spring is attached to one of them, and the blocks are pushed together with the spring between them. A cord holding them together is burned, after which the block of mass 10 kg moves to the right with a speed of 3.4 m/s. What is the velocity of the other mass in

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lublana

Answer:

5.67 m/s ( towards left)

Explanation:

We are given that

[tex]m_1=6 kg[/tex]

[tex]m_2=10 kg[/tex]

Speed of mass 10 kg=3.4 m/s

We have to find the velocity of other mass.

When there is no external force applied the the linear momentum will be conserved

[tex]-m_2v_2=m_1v_2[/tex]

Substitute the values

[tex]10\times 3.4=6v_1[/tex]

[tex]v_1=-\frac{10\times 3.4}{6}[/tex]

[tex]v_1=-5.67 m/s[/tex]

The mass 6 kg moves to the left with speed 5.67 m/s.

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