Answer:
The wavelength is [tex]\lambda = 586nm[/tex]
Explanation:
From the question we are told
The slit spacing is [tex]d =1.05mm = \frac{1.05}{1000} = 1.05*10^{-3}m[/tex]
The distance from the screen [tex]L = 8.91m[/tex]
The distance from central bright fringe [tex]y_n = 4.97cm = \frac{4.97}{100} = 0.0497m[/tex]
The order of the bright fringe [tex]n = 10[/tex]
Generally the position of a bright fringe is mathematically represented as
[tex]y_n = n\frac{\lambda L }{d}[/tex]
Where [tex]\lambda[/tex] is the wavelength
Making [tex]\lambda[/tex] the subject
[tex]\lambda = \frac{y_n d}{nL}[/tex]
substituting value
[tex]\lambda = \frac{0.0497 * 1.05 *10^{-3}}{10 * 8.91}[/tex]
[tex]\lambda = 586nm[/tex]
