Respuesta :
Answer:
There is 95% confidence that the true value of the population proportion is included in the interval (0.33, 0.45).
Step-by-step explanation:
The (1 - α)% confidence interval for population parameter implies that there is a (1 - α) probability that the true value of the parameter is included in the interval.
Or, the (1 - α)% confidence interval for the parameter implies that there is (1 - α)% confidence or certainty that the true parameter value is contained in the interval.
The 95% confidence interval for the population proportion is calculated to be 0.39 ± 0.06.
The interval is:
CI = (0.33, 0.45)
This confidence interval implies that, there is 0.95 probability that the true value of the population proportion is included in the interval (0.33, 0.45).
Or, there is 95% confidence that the true value of the population proportion is included in the interval (0.33, 0.45).
Using confidence interval concepts, it is found that we can be 95% sure that the true population proportion is within 6% of 39%.
A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. The interpretation is that we are x% confident that the population mean is between a and b, or even within the margin of error of the proportion.
In this problem, interval within 0.06 of 39%, hence:
The interpretation is that we can be 95% sure that the true population proportion is within 6% of 39%.
A similar problem is given at https://brainly.com/question/15043877
