Given:
The given function is
[tex]y = 200(1.06)^x[/tex]
To find whether the function is growth or decay and the growth of decay.
Formula:
The function [tex]a(1+r )^x[/tex] is said to be an exponential growth, if the value of a > 0 and r > 0
Again, the function [tex]a(1-r )^x[/tex] is said to be an exponential decay, if the value of a > 0 and 0 < r < 1.
Now,
[tex]y = 200(1.06)^x[/tex]
[tex]y = 200(1+0.06)^x[/tex]
Thus, the value of a > 0 and r > 0, then the given function is an exponential growth function.
Therefore,
The given function is an exponential growth function.
