Answer : The pre-exponential factor in the Arrhenius equation is, 14.99 s⁻¹
Explanation :
Using Arrhenius equation,
[tex]K=A\times e^{\frac{-Ea}{RT}}[/tex]
Taking ln on both the sides, we get:
[tex]\ln K=\frac{-Ea}{RT}+\ln A[/tex]
where,
K = rate constant = [tex]15.0s^{-1}[/tex]
Ea = activation energy = 1.104 J/mol
T = temperature = 300 K
R = gas constant = 8.314 J/mole.K
A = Arrhenius constant
Now put all the given values in the above formula, we get the value of \ln a.
[tex]\ln (15.0s^{-1})=\frac{1.104J/mol}{(8.314J/mole.K)\times (300K)}+\ln A[/tex]
[tex]\ln A=2.708s^{-1}[/tex]
[tex]A=14.99s^{-1}[/tex]
Therefore, the pre-exponential factor in the Arrhenius equation is, 14.99 s⁻¹
