Respuesta :
Answer:
Explanation:
In case of gas , work done
W = ∫ p dV , p is pressure and dV is small change in volume
the limit of integration is from Vi to Vf .
= ∫ p dV
= ∫ p₀[tex]V^{-\frac{6}{5}[/tex] dV
= p₀ [tex]V^{-\frac{6}{5} +1}[/tex] / ( [tex]\frac{-6}{5} +1[/tex] )
= - 5p₀ [tex]V^{-\frac{1}{5}[/tex]
Taking limit from Vi to Vf
W = - 5 p₀ ( [tex]V_f^\frac{-1}{5} - V_i^{\frac{-1}{5}[/tex] ) ltr- atm.
An expression for the work W done on the gas when the gas is compressed from a volume Vi to a volume Vf is =- 5 p₀ ( Vf -1/5 - Vi 1/5 ) ltr- atm.
What is the Process of Oxygen Gas?
In the case of gas, When the work done is:
Then, W = ∫ p dV, p is pressure and dV is a small change in volume
After that, The limit of integration is from Vi to Vf.
= ∫ p dV
= ∫ p dV - 6/5 dV
= ∫ p₀ d -6/5+1 / (-6/5 + 1)V
= - 5p₀ Vf -1/5
Now Taking the limit from Vi to Vf
Therefore, W = - 5 p₀ ( Vf -1/5 - Vi 1/5 ) ltr- atm.
Find more information about Process of Oxygen Gas here:
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