Answer:
D tortoiseshell female; black male
Explanation:
Let the allele for black fur color be B, the alternate version (orange color) will be b while a Bb will appear tortoise shell in color.
Black female = [tex]X^BX^B[/tex]
Orange male = [tex]X^bY[/tex]
Crossing a black female with an orange male:
[tex]X^BX^B[/tex] x [tex]X^bY[/tex]
Offspring
[tex]X^BX^b[/tex] tortoise shell female
[tex]X^BY[/tex] black male
[tex]X^BX^b[/tex] tortoise shell female
[tex]X^BY[/tex] black male.
All the females from the cross will be tortoise shell in appearance while all the males will be black.
The correct option is D.
Answer:
The kind of offspring to expect will be tortoiseshell female and black male.
Explanation:
X linked alleles are normally passed from mother to sons and fathers to daughters.
In cats, black fur colour is caused by an X-linked allele: the other allele at this locus causes orange colour. the heterozygote is tortoiseshell.
Both the black fur colour and the orange fur colour will be inherited in the homozygous dominant form. Thus, we have:
Black female: XBXB Black male: XBY
orange female: XRXR orange male: XRY
The heterozygote: XBXR (female). No heterozygote male as the males only possess one X chromosomes. so they are either black or orange.
A cross between black female and an orange male gives:
XB XB
XR XBXR XBXR
Y XBY XBY
The kind of offspring to expect will be tortoiseshell female (an heterozygote) and black male.
