Answer:
15.0 moles of silver chloride are produced from 15.0 mol of silver nitrate.
The number of mole of silver chloride, AgCl produced from the reaction is 15 moles.
AgNO₃ + NaCl —> NaNO₃ + AgCl
From the balanced equation above,
1 mole of AgNO₃ reacted to produce 1 mole of AgCl.
With the above information, we can obtain the number of mole of AgCl produced by the reaction of 15 moles of AgNO₃. This can be obtained as follow:
From the balanced equation above,
1 mole of AgNO₃ reacted to produce 1 mole of AgCl.
Therefore,
15 moles of AgNO₃ will also react to produce 15 moles of AgCl.
Thus, 15 moles of AgCl were obtained from the reaction.
Learn more about stoichiometry: https://brainly.com/question/25910524
