Answer:
1. 4,000 bags
2. 1,000
3. 180 runs
4. 18,000
5. $165,600
Explanation:
1.
Q = [tex]\sqrt{2*D*S/C*(1-D/N/P)}[/tex]
[tex]\sqrt{2*36,000*200/3.6*(1-36,000/240/200)}[/tex]
[tex]\sqrt{16,000,000}[/tex]
= 4,000 bags
2.
Maximum Inventory = Q* (1 - D/N/P)
4,000*0.25
= 1,000
3.
Annual demand / Bags of coffee roasted per day
36,000 bags / 200 bags
= 180 runs
4.
Annual average inventory
36,000/2
=18,000
5.
Production Cost $200 * 180 runs = $36,000
Carrying Cost $3.6 * 36,000 bags = $129,600
Total Cost = $36,000 + $129,600
= $165,600