Answer:e n = 3 to n = 2 = 486 nm
n = 4 to n = 2 = 656 nm
Explanation: Solution
E = hf = hc/λ.
Here h = 6.626*10-34J/S ,
C= Speed of ligfht=3*10^8m/s and
λ = wavelength
Since h and c are constants, we now have that the energy of photon is inversely proportional to the wavelengths of the speed of light .
E ᵅ 1/ λ ie higher energy given lower wavelength
In this question, we were given wavelengths of 656 nm and 486 nm
The principle is that The transitions between orbit that are closer together produce lower energy lights and therefore higher wavelengths than orbits that are further apart.
Therefore For transition due to the n = 3 to n = 2, it will have wavelength number of 486 nm since orbits are closer.
For transition due to the n = 4 to n = 2, it will have wavelength number of 656 nm since orbits are farther apart
