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When 1.98 g of NaOH (molar mass= 40 g/mole) are added to 75.0 mL of a 0.350 M HCl solution in a coffee-cup calorimeter, the temperature changes from 21.7°C to 25.8°C. If the resulting solution has a mass of 78.2 grams and a specific heat capacity of 3.97 J/g°C, what is the enthalpy change (ΔHrxn) for this reaction in kJ/mole.

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Answer:

(ΔHrxn) = 1.273kJ/mol

Explanation:

Applying

m=78.2, c= 3.97, ∆t= 25.8-21.7

(ΔHrxn)= mc∆t

=78.2× 3.97× 4.1= 1.273kJ/mol

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