Silicon carbide (SiC) is an important ceramic material made by reacting sand (silicon dioxide, SiO2) with powdered carbon at a high temperature. Carbon monoxide is also formed. When 100.0 kg of sand is processed, 51.4 kg of SiC is recovered. What is the percent yield of SiC from this process

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21-04-2020
Chemistry

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Silicon carbide (SiC) is an important ceramic material made by reacting sand (silicon dioxide, SiO2) with powdered carbon at a high temperature. Carbon monoxide is also formed. When 100.0 kg of sand is processed, 51.4 kg of SiC is recovered. What is the percent yield of SiC from this process

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OrethaWilkison OrethaWilkison · Answer 1 · 2020-04-25T07:40:48+02:00

Answer:

Percent yield of SiC is 77.0%.

Explanation:

Balanced reaction: [tex]SiO_{2}+3C\rightarrow SiC+2CO[/tex]

Molar mass of SiC = 40.11 g/mol

Molar mass of [tex]SiO_{2}[/tex] = 60.08 g/mol

So, 100.0 kg of [tex]SiO_{2}[/tex] = [tex]\frac{100.0\times 10^{3}}{60.08}[/tex] moles of [tex]SiO_{2}[/tex] = 1664 moles of [tex]SiO_{2}[/tex]

According to balanced equation, 1 mol of [tex]SiO_{2}[/tex] produces 1 mol of SiC

Therefore, 1664 moles of [tex]SiO_{2}[/tex] produce 1664 moles of SiC

Mass of 1664 moles of SiC = [tex](1664\times 40.11)g[/tex] = 66743g = 66.74 kg (4 sig. fig.)

Percent yield of SiC = [(actual yield of SiC)/(theoretical yield of SiC)][tex]\times 100[/tex]%

= [tex]\frac{51.4kg}{66.74kg}\times 100[/tex] %

= 77.0%

shrutiagrawal1798 shrutiagrawal1798 · Answer 2 · 2021-12-09T10:17:28+01:00

The percentage yield of silicon carbide has been 77%.

The balanced chemical equation for the reaction has been:

[tex]\rm SiO_2\;+\;3\;C\;\rightarrow\;SiC\;+\;2\;CO[/tex]

From the balanced equation, the 1 moles of Silicon dioxide forms 1 mole of Silicon carbide.

The moles of Sand (Silicon dioxide) used has been:

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

Moles of Silicon dioxide = [tex]\rm \dfrac{100\;\times\;1000\;grams}{60.08\;g/mol}[/tex]

Moles of Silicon dioxide = 1664 mol.

From the equation :

1 mole Silicon dioxide = 1 mole Silicon carbide.

1664 moles Silicon dioxide = 1664 mole Silicon carbide.

The mass of 1664 mole Silicon carbide has been:

Mass = moles × molecular weight

Mass = 1664 × 40.11 g/mol

Mass of Silicon carbide = 66743 grams

Mass of Silicon carbide = 66.74 kg.

The theoretical yield of Silicon carbide = 66.74 kg.

The actual yield of Silicon carbide = 51.4 kg.

The percentage yield can be expressed as:

Percentage yield = [tex]\rm \dfrac{Actual\;yield}{Theoretical\;yield}\;\times\;100[/tex]

The percentage yield of silicon carbide = [tex]\rm \dfrac{51.4}{66.74}\;\times\;100[/tex]

The percentage yield of silicon carbide = 77%.

The percentage yield of silicon carbide has been 77%.

For more information about the percentage yield, refer to the link:

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