Step-by-step explanation:
To find the sum of first 20 terms,
a = 6, r = 3
By formula, [tex]S_{n} = \frac{a(r^{n}-1) }{r-1}[/tex]
substitute the values in the above formula, the equation becomes,
[tex]S_{20} = \frac{6(3^{20}-1) }{3-1}[/tex]
[tex]S_{20} = \frac{6(3^{20}-1) }{2}[/tex]
[tex]S_{20}[/tex] = [tex]{3(3^{20}-1) }[/tex]