What is the value of AAA when we rewrite \left(\dfrac {6}{17}\right)^{9x}( 17 6 ​ ) 9x (, start fraction, 6, divided by, 17, end fraction, ), start superscript, 9, x, end superscript as A^{x}A x A, start superscript, x, end superscript ?

Respuesta :

We have been given an expression [tex]\left(\dfrac {6}{17}\right)^{9x}[/tex]. We are asked to find the value of A when rewrite our given expression as [tex]A^{x}[/tex].

To solve our given problem, we will use exponent properties.

Using exponent property [tex]a^{mn}=(a^m)^n[/tex], we can rewrite our given expression as:

[tex]\left(\dfrac {6}{17}\right)^{9x}=\left(\left(\dfrac {6}{17}\right)^9\right)^{x}[/tex]

Now, we will compare our expression with  [tex]A^{x}[/tex].

Upon comparing [tex]\left(\left(\dfrac {6}{17}\right)^9\right)^{x}[/tex] with [tex]A^{x}[/tex], we can see that [tex]A=\left(\dfrac {6}{17}\right)^9[/tex].

Therefore, the value of A is [tex]\left(\dfrac {6}{17}\right)^9[/tex].

We can further simplify [tex]\left(\dfrac {6}{17}\right)^9[/tex] as:

[tex]\left(\dfrac {6}{17}\right)^9=\frac {6^9}{17^9}=\frac{10077696}{118587876497}[/tex]

The value of A is [tex]\left( \dfrac{6}{17}\right)^{9}[/tex].

Given that,

Equation; [tex]\rm \left(\dfrac{6}{17}\right)}^{9x}[/tex]

We have to find,

The value of A when the function is written as [tex]\rm A^x[/tex]?

According to the question,

To determine the value [tex]A^x[/tex] by applying the exponent property in the equation following all the steps given below.

By using the exponent property rewrite the equation,

[tex]\rm \left ( a )\right ^{mn} = ( a^m )\right^{n}[/tex]

Applying the property in the equation,

[tex]\rm \left(\dfrac{6}{17}\right)}^{9x}= \left( \left(\dfrac{6}{17}\right)^{9}\right) \right)^{x}[/tex]

By comparing the equation with [tex](A)^{x}[/tex],

[tex]\rm A ^{x}= \left( \left(\dfrac{6}{17}\right)^{9}\right) \right)^{x}\\\\A = \left( \dfrac{6}{17}\right)^{9}[/tex]

Hence, The required value of A is [tex]\left( \dfrac{6}{17}\right)^{9}[/tex].

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https://brainly.com/question/1807508