Respuesta :
Answer:
The particle's velocity is 212.15 m/s.
Explanation:
Given that,
Charge of particle, [tex]q=6.41\ \mu C=6.41\times 10^{-6}\ C[/tex]
The magnitude of electric field, E = 1270 N/C
The magnitude of magnetic field, B = 1.28 T
Net force, [tex]F=6.4\times 10^{-3}\ N[/tex]
We need to find the magnitude of the particle's velocity. the net force acting on the particle is given by Lorentz force as :
[tex]F=qE+qvB\\\\v=\dfrac{F-qE}{qB}\\\\v=\dfrac{6.4\times 10^{-3}-6.41\times 10^{-6}\times 1270}{6.41\times 10^{-6}\times 1.28}\\\\v=-212.15\ m/s[/tex]
So, the particle's velocity is 212.15 m/s.
