Answer:
Four (4)
Explanation:
Assuming the allele for black fur color is represented by B, the alternate will be b.
Assuming the allele for active behavior is A, the alternate will be a.
Assuming the allele for light eyes color is L, the alternate will be l.
A male is heterozygous for the dominant traits of black fur and active behavior but is homozygous recessive for light eyes.
Heterozygous for black fur = Bb
Heterozygous for active behavior = Aa
Homozygous recessive for light eyes = ll
Hence, the genotype of the male is BbAall
Possible gametes:
BAl
Bal
bAl
bal
Hence, 4 types of gametes are produced by the male.
Answer:
The male mouse would produce four possible combinations of gametes in equal proportions which includes: BAd, Bad, bAd and bad.
Explanation:
let B- black fur, A- active behaviour and D-dark eyes
The male mouse is heterozygous for dominant traits of black fur and active behavior but is homozygous recessive for light eyes.
Thus the genotype will be: BbAadd
The female mouse is heterozygous for dark eyes, has white fur, and displays lazy behavior. thus the genotype wil be: bbaaDd
The male mouse would produce four possible combinations of gametes in equal proportions which includes: BAd, Bad, bAd and bad
