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A 15 A current is directed along the positive x-axis and perpendicular to a uniform magnetic field. The conductor experiences a magnetic force per unit length of 0.20 N/m in the negative y direction. Calculate the magnitude of the magnetic field in the region through which the current passes. Answer in units of T.

Respuesta :

Answer:

The magnitude of magnetic field in the region through the current passes is 0.0133 T

Explanation:

Given:

Current [tex]I = 15[/tex] A

Force per unit length [tex]\frac{F}{l} = 0.20 \frac{N}{m}[/tex]

The magnetic force on current carrying conductor is given by,

   [tex]F = IlB[/tex]

For finding the magnetic field,

   [tex]B = \frac{F}{Il}[/tex]

   [tex]B = \frac{0.20}{15}[/tex]

   [tex]B = 0.0133[/tex] T

Therefore, the magnitude of magnetic field in the region through the current passes is 0.0133 T

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