Answer:
0.875
Step-by-step explanation:
Definition
The conditional Probability of an event A given that event B has occurred is:
[tex]P(A|B)=\frac{P(A\cap B)}{P(B)} , P(B)\neq 0[/tex]
Let A=Event of Withdrawing Cash.
B=Event of Checking Account Balance.
We want to determine the probability that given a woman checks her account balance, she also gets cash. i.e. P(A|B)
[tex]P(A)=0.92, P(B)=0.32, P(A\cup B)=0.96\\P(A\cup B)=P(A)+P(B)-P(A\cap B)\\0.96=0.92+0.32-P(A\cap B)\\P(A\cap B)=0.92+0.32-0.96=0.28[/tex]
Therefore:
[tex]P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{0.28}{0.32} =0.875[/tex]
