Be sure to answer all parts. Use MO diagrams to place C2−, C2, C2+ in order of the following properties: (a) increasing bond energy C2− < C2 < C2+ C2− < C2+ < C2 C2 < C2− < C2+ C2 < C2+ < C2− C2+ < C2 < C2− C2+ < C2− < C2 (b) increasing bond length C2− < C2 < C2+ C2− < C2+ < C2 C2 < C2− < C2+ C2 < C2+ < C2− C2+ < C2 < C2− C2+ < C2− < C2

Bond energy (E) is defined as the amount of energy required to break apart a mole of molecules into its component atoms. It is a measure of the strength of a chemical bond.

pstnonsonjoku pstnonsonjoku · Answer 2 · 2021-11-30T20:43:57+01:00

The higher the bond order, the shorter the bond length and the greater the bond energy.

The molecular orbital configuration of a chemical specie shows the arrangement of electrons in such a specie into molecular orbitals in accordance with the Aufbau principle.

For C2;

σ1s2 σ*1s2 σ2s2 σ*1s2 π2py2 π2pz2

Bond order = 1/2(8 - 4) = 2

For C2^-;

σ1s2 σ*1s2 σ2s2 σ*1s2 π2py2 π2pz2 σ2px1

Bond order = 1/2(9 - 4) = 2.5

For C2^+;

σ1s2 σ*1s2 σ2s2 σ*1s2 π2py2 π2pz1

Bond order = 1/2(7 - 4) = 1.5

We must recall that the higher the bond order, the shorter the bond length and the greater the bond energy. Hence;

a) In order of increasing bond energy; C2^+ < C2 < C2^-

b) In order of increasing bond length; C2^- < C2 < C2^+

Learn more: https://brainly.com/question/20906233