Respuesta :
Answer:
a. Smallest photon energy = 0.04 eV
b. Next larger photon energy = 0.08 eV
c. Largest photon energy = 0.12 eV
Explanation:
Since the spacing between the levels is 0.04 even
The smallest photon energy, E= 0.04 eV
The next larger photon energy = 2E = 2×0.04 = 0.08 eV
Largest photon energy = 3E = 3×0.04 = 0.12
The relationships for the atomic transitions allowed to find all the transitions in the four-level system are:
- The minimum energy is: E = 0.04 eV.
- Tthe following is: E = 0.08 eV.
- Tthe maximum energy is: E = 0.12 eV.
Atomic Transitions are the energy deference between two specific atomic levels.
[tex]\Delta E = E_f - E_i[/tex]
They indicate that we have 4 equally spaced states with an energy difference of 0.04 eV between each one.
In the attachment we can see a diagram of the system with an arrow indicating the possible transitions.
From level n = 2 to level n = 1 the energy is E₂₁ = 0.04 eV.
from level n = 3 to n = 1 the energy is E₃₁ = 0.08 eV.
all other transitions in the table.
Initial state final state Energy (eV)
4 1 0.12
3 1 0.08
2 1 0.04
4 2 0.08
3 2 0.04
4 3 0.04
These are all the possible transitions, we can see that some energies have several possible states, these currents that have several possibilities are called degenerate.
the energies are:
the minimum is: E = 0.04 eV.
the following is: E = 0.08 eV.
the maximum is E: = 0.12 eV.
In conclusion using the relationships for the atomic transitions we can find all the transitions in the four-level system are:
- The minimum energy is: E = 0.04 eV
- The following is: E = 0.08 eV
- Tthe maximum energy is: E = 0.12 eV
Learn more here: brainly.com/question/19426165
