Answer:
Explanation:
Given
Volume of bucket [tex]V=10\ gallon[/tex]
Time taken to fill the bucket [tex]t=50\ s[/tex]
so volume flow rate is [tex]\dot{V}=\frac{10}{50}=0.2\ gal/s[/tex]
1 gal is equivalent to [tex]0.133\ ft^3[/tex]
[tex]\dot{V}=0.0267\ ft^3/s[/tex]
mass flow rate [tex]\dot{m}=\rho \times \dot{V}[/tex]
[tex]\dot{m}=62.4\times 0.0267[/tex]
[tex]\dot{m}=1.668\ lbs[/tex]
(b)Average velocity through nozzle exit
[tex]\dot{V}=Av_{avg}[/tex]
[tex]v_{avg}=\dfrac{0.0267}{\frac{\pi}{4}\times (0.0262)^2}[/tex]
[tex]v_{avg}=49.51\ ft/s[/tex]
