Respuesta :
Answer:
2.5 mg
Step-by-step explanation:
We are given that
A=Initial amount=10 mg
Half life,h=8 days
We have to find the mass of radioactive isotope remains after 16 days.
t=16 days
We know that the amount of radioactive isotope after t days is given by
[tex]P(t)=A(1\frac{1}{2}^{\frac{t}{h})[/tex]
Using the formula
[tex]P(t)=10(\frac{1}{2}^{\frac{16}{8}})[/tex]
[tex]P(t)=10\times (\frac{1}{2})^2[/tex]
[tex]P(t)=2.5 mg[/tex]
Answer:
its b on edg
Step-by-step explanation:
its B I answered the question on my test and got it correct