Respuesta :
Answer:
Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] [tex]\geq[/tex] $13.04
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < $13.04
Step-by-step explanation:
We are given that the mean cost of a flank steak, broccoli, and rice bought at the grocery store is $13.04.
A sample of 100 neighborhood restaurants showed a mean price of $12.65 and a standard deviation of $2 for a comparable restaurant meal.
Let [tex]\mu[/tex] = mean cost of a restaurant meal
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] [tex]\geq[/tex] $13.04
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < $13.04
Here, null hypothesis states that the mean cost of a restaurant meal is more than or equal to fixing a comparable meal at home.
On the other hand, alternate hypothesis states that the mean cost of a restaurant meal is less than fixing a comparable meal at home.
The test statistics that we can use for conducting this hypothesis would be t test statistics as we don't know about population standard deviation;
T.S. = [tex]\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
where, [tex]\bar X[/tex] = sample mean price of a restaurant meal $12.65
s = sample standard deviation = $2
n = sample of neighborhood restaurants = 100
