2.04 atm is the pressure of the nitrogen gas in the container when 0.316 mol sample of nitrogen gas, N2 (g), is placed in a 4.00 L container at 315 K.
Explanation:
Data given:
moles of nitrogen gas, n = 0.316
volume of the nitrogen gas, V = 4 litres
temperature of the container of nitrogen gas = 315 K
R (gas constant) = 0.08201 Latm/mole K
Pressure of the nitrogen gas on the container, P = ?
from the data given, we will apply ideal gas law equation to calculate the pressure on the nitrogen gas:
PV = nRT
Rearranging the equation,
P = [tex]\frac{nRT}{V}[/tex]
P = [tex]\frac{0.316 X 0.08201 X 315}{4}[/tex]
P = 2.04 atm
The pressure of the nitrogen gas in the container is 2.04 atm.
