Respuesta :
Answer:
Option D) 0.65
Step-by-step explanation:
We are given the following in the question:
Percentage of executives who read Time magazine = 35%
[tex]P(M) = 0.35[/tex]
Percentage of executives who read U.S. News & World Report = 40%
[tex]P(N) = 0.4[/tex]
Percentage of executives who read both Time magazine and U.S. News & World Report = 10%
[tex]P(M\cap N) = 0.1[/tex]
We have to find the probability that a particular top executive reads either Time or U.S. News & World Report regularly.
Thus, we have to evaluate,
[tex]P(M\cup N) = P(M) + P(N) -P(M\cap N)[/tex]
Putting values, we get,
[tex]P(M\cup N) = 0.35 + 0.4 - 0.1=0.65[/tex]
0.65 is the probability that a particular top executive reads either Time or U.S. News & World Report regularly.
Thus, the correct answer is
Option D) 0.65
